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Martin Geisler authored
When calling encode on a str, the string is first decoded using the
default encoding and then encoded. So

  s.encode('ascii') == s.decode().encode('ascii')

We don't care about the encode step here -- we're just after the
UnicodeDecodeError raised by decode if it finds a non-ASCII character.

This way is also marginally faster since it saves the construction of
the extra str object.
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